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How to produce a symmetric & semi (pan)magic 5x5x5 cube
The first known perfect magic cube of order 5

Walter Trump and Christian Boyer, 2003-11-13
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The above mentioned 5x5x5 magic cube has the following magic features:
- the 5 rows, the 5 columns and the 2 diagonals in each level give the magic sum of 315:
- the 25 pillars give the magic sum of 315;
- the 20 diagonals (for example 115+64+38+87+11=315 or 106+44+58+87+20=315) through
the 5 levels give the magic sum of 315;
- The four space diagonals (for example 67+39+63+87+59=315) give the magic sum of 315.
Use the method to produce a panmagic 5x5 square also to produce a symmetric & semi (pan)magic 5x5x5 cube.
If you want a symmetric (& semi [pan]magic) cube, put in the 1st row of the 1st level of the 1st grid the
middle digit of 0 up to 4, that is 2, on the 1st position (from the left), and put the other digits in a 'symmetric'
order, for example: 2-3-4-0-1.
If you want only a panmagic cube, put in the 1st row of the 1st level of the 1st grid the 2 on the 1st position
and put the other digits in random order (i.e. 2-1-3-0-4).
Make row 2 up to 5 of the 1st level of the 1st grid by moving the 1st row each time ([5+1]/2 = ) 3 places to the
left. Make level 2 up to 5 of the 1st grid by moving the columns of the 1st level each time 2 places to the left.
If you want a symmetric (& semi [pan]magic) cube, put in the 1st row of the 1st level of the 2nd grid the
middle digit of 0 up to 4, that is 2, on the 3rd position (from the left) and put the other digits in a 'symmetric'
order, for example: 0-1-2-3-4.
If you want only a panmagic cube, put in the 1st row of the 1st level of the 1st grid the 2 on the 3rd position
and put the other digits in random order (i.e. 4-0-2-3-1).
Make row 2 up to 5 of the 1st level of the 2nd grid by moving the 1st row each time ([5+1]/2 = ) 3 places to the
right. Make level 2 up to 5 of the 2nd grid by moving the columns of the 1st level each time 2 places to the left.
The 3rd grid is the same as the 2nd grid, but the sequence of the levels is 5 up to 1 (in stead of 1 up
to 5).
Take 1x digit from the 1st grid + 5x digit from the 2nd grid + 25x digit from the 3rd grid and the symmetric &
semi (pan)magic 5x5x5 cube is ready.
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1x digit +1 + 5x digit + 25x digit = 5x5x5 cube, 1st level
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2
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3
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4
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0
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1
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0
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1
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2
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3
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4
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3
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4
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0
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1
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2
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78
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109
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15
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41
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72
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4
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0
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1
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2
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3
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3
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4
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0
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1
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2
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1
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2
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3
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4
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0
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45
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71
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77
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108
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14
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1
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2
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3
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4
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0
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1
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2
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3
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4
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0
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4
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0
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1
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2
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3
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107
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13
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44
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75
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76
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3
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4
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0
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1
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2
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4
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0
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1
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2
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3
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2
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3
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4
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0
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1
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74
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80
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106
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12
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43
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0
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1
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2
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3
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4
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2
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3
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4
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0
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1
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0
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1
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2
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3
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4
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11
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42
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73
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79
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110
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1x digit +1 + 5x digit + 25x digit = 5x5x5 cube, 2nd level
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4
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0
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1
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2
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3
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2
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3
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4
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0
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1
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1
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2
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3
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4
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0
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40
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66
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97
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103
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9
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1
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2
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3
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4
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0
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0
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1
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2
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3
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4
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4
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0
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1
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2
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3
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102
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8
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39
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70
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96
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3
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4
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0
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1
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2
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3
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4
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0
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1
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2
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2
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3
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4
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0
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1
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69
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100
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101
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7
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38
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0
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1
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2
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3
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4
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1
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2
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3
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4
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0
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0
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1
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2
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3
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4
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6
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37
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68
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99
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105
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2
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3
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4
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0
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1
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4
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0
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1
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2
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3
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3
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4
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0
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1
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2
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98
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104
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10
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36
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67
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1x digit +1 + 5x digit + 25x digit = 5x5x5 cube, 3th level
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1
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2
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3
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4
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0
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4
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0
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1
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2
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3
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4
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0
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1
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2
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3
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122
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3
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34
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65
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91
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3
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4
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0
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1
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2
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2
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3
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4
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0
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1
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2
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3
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4
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0
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1
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64
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95
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121
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2
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33
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0
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1
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2
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3
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4
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0
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1
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2
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3
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4
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0
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1
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2
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3
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4
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1
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32
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63
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94
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125
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2
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3
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4
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0
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1
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3
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4
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0
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1
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2
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3
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4
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0
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1
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2
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93
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124
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5
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31
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62
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4
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0
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1
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2
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3
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1
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2
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3
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4
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0
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1
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2
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3
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4
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0
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35
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61
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92
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123
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4
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1x digit +1 + 5x digit + 25x digit = 5x5x5 cube, 4th level
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3
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4
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0
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1
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2
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1
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2
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3
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4
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0
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2
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3
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4
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0
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1
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59
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90
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116
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22
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28
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0
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1
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2
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3
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4
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4
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0
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1
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2
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3
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0
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1
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2
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3
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4
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21
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27
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58
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89
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120
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2
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3
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4
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0
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1
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2
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3
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4
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0
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1
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3
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4
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0
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1
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2
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88
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119
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25
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26
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57
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4
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0
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1
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2
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3
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0
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1
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2
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3
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4
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1
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2
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3
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4
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0
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30
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56
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87
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118
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24
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1
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2
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3
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4
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0
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3
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4
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0
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1
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2
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4
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0
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1
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2
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3
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117
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23
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29
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60
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86
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1x digit +1 + 5x digit + 25x digit = 5x5x5 cube, 5th level
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0
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1
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2
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3
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4
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3
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4
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0
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1
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2
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0
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1
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2
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3
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4
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16
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47
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53
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84
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115
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2
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3
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4
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0
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1
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1
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2
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3
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4
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0
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3
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4
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0
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1
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2
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83
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114
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20
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46
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52
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4
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0
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1
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2
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3
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4
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0
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1
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2
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3
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1
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2
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3
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4
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0
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50
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51
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82
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113
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19
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1
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2
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3
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4
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0
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2
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3
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4
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0
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1
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4
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0
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1
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2
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3
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112
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18
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49
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55
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81
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3
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4
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0
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1
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2
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0
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1
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2
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3
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4
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2
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3
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4
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0
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1
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54
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85
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111
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17
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48
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Less & extra magic features:
- The diagonals through the levels from up to down and down to up give not the magic sum;
- The pandiagonals in the levels give the magic sum of 315;
- The pandiagonals through the levels from left to right and right to left give the magic sum of 315;
- The 5x5x5 cube is [fully] symmetric.
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