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Perfect magic squares
Basic key method (2)
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How to produce squares that are odd multiples of 4
 
 
Why does the basic key method of construction lead to a perfect 16x16 Franklin panmagic square?
Why does the basic key method lead to perfect Franklin panmagic squares that are multiples of 8, for example
the perfect 16x16 Franklin pan magic square.
 
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16 = 136.
 
 
(1st) sum = sum = 34 = 1/4 x 136

 
1
2
16
15
16
15
1
2

 
That is the condition which ensures that the sum of the digits of the quarter rows and the quarter columns is a
quarter of the magic sum.
 
 
(2nd) sum = sum = 34 = 1/4 x 136

 
1
2
16
15
16
15
1
2

 
That is the condition which ensures that the sum of the digits of the quarter diagonals (and the [parallel] [mir-
rored] bent diagonals) is a quarter of the magic sum.
 
 
(3rd) An odd number of digits must always be between reverse vertical combinations of digits (reverse vertical
combinations may not lie next to each other).
 
 
1
2
16
15
16
15
1
2

 
This is the condition that allows it to be used as a second (column) square, thus rotate the first (row) square
by a quarter turn to the left and all the digits from 1 to 256 can be found in the square.
 
 
How to use the basic key method of construction for the 12x12 square?
For squares that are odd multiples of 4, for example the 12x12 square, it is not possible to comply with all three
above-mentioned conditions. You must choose between the following:

 
[option a]
 
(1st) ) sum = sum = 26 = 1/3 x 78

 
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4

 
This is the condition which ensures that the sum of the digits of 1/3 rows and 1/3 columns are 1/3 of the magic
sum, but the sum of the digits of 1/2 rows and 1/2 columns are not ½ of the magic sum. Besides, the sum of the
digits of circles and other symmetric figures are a proportional part of the magic sum.
 
 
(2nd) sum = sum = 39 = 1/2 x 78

 
1
10
11
4
8
6
12
3
2
9
5
7

 
This is the condition which ensures that the sum of the digits of ½ diagonals (and the [parallel] [mirrored] bent
diagonals) is ½ of the magic sum.
 
 
(3rd) This is the condition that allows it to be used as second (column) square, thus rotate the first (row) square
by a quarter turn to the left, and you will find all the digits from 1 to 144 can be found in the square.
 
 
Row pattern
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
1
10
11
4
8
6
5
7
12
3
2
9
12
3
2
9
5
7
8
6
1
10
11
4
 
  
Column pattern
9
4
9
4
9
4
9
4
9
4
9
4
2
11
2
11
2
11
2
11
2
11
2
11
3
10
3
10
3
10
3
10
3
10
3
10
12
1
12
1
12
1
12
1
12
1
12
1
7
6
7
6
7
6
7
6
7
6
7
6
5
8
5
8
5
8
5
8
5
8
5
8
6
7
6
7
6
7
6
7
6
7
6
7
8
5
8
5
8
5
8
5
8
5
8
5
4
9
4
9
4
9
4
9
4
9
4
9
11
2
11
2
11
2
11
2
11
2
11
2
10
3
10
3
10
3
10
3
10
3
10
3
1
12
1
12
1
12
1
12
1
12
1
12
 
 
12x12 square (option a)
97
46
107
40
104
42
101
43
108
39
98
45
24
123
14
129
17
127
20
126
13
130
23
124
25
118
35
112
32
114
29
115
36
111
26
117
144
3
134
9
137
7
140
6
133
10
143
4
73
70
83
64
80
66
77
67
84
63
74
69
60
87
50
93
53
91
56
90
49
94
59
88
61
82
71
76
68
78
65
79
72
75
62
81
96
51
86
57
89
55
92
54
85
58
95
52
37
106
47
100
44
102
41
103
48
99
38
105
132
15
122
21
125
19
128
18
121
22
131
16
109
34
119
28
116
30
113
31
120
27
110
33
12
135
2
141
5
139
8
138
1
142
11
136
 
 
[option b]
 
(1st) sum = sum = 39 = 1/2 x 78
 
 
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8

 
This is the condition which ensures that the sum of the digits of ½ rows and ½ columns are ½ of the
magic sum. Besides, the sum of the digits of circles and other symmetric figures are not a proportional
part of the magic sum.
 
(2nd) The sum of the ½ twisting rows is not 39, but the sum of the whole twisting rows is 78. That is
the boundary condition which ensures that the sum of the digits of the whole diagonal is the magic sum,
but the sum of the digits of ½ diagonals (and the [parallel] [mirrored] bent diagonals) is not ½ of the
magic sum.
 
(3rd) Odd number of digits are between reverse vertical combinations rotating the first (row) square by
a quarter turn to the left enables you to use it as a second (column) square and all the digits from 1 to
144 can be found in the square.
 
 
Row pattern
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
1
11
10
2
7
8
12
4
3
9
6
5
12
2
3
11
6
5
1
9
10
4
7
8
 
 
Colum pattern
5
8
5
8
5
8
5
8
5
8
5
8
6
7
6
7
6
7
6
7
6
7
6
7
9
4
9
4
9
4
9
4
9
4
9
4
3
10
3
10
3
10
3
10
3
10
3
10
4
9
4
9
4
9
4
9
4
9
4
9
12
1
12
1
12
1
12
1
12
1
12
1
8
5
8
5
8
5
8
5
8
5
8
5
7
6
7
6
7
6
7
6
7
6
7
6
2
11
2
11
2
11
2
11
2
11
2
11
10
3
10
3
10
3
10
3
10
3
10
3
11
2
11
2
11
2
11
2
11
2
11
2
1
12
1
12
1
12
1
12
1
12
1
12
 
 
12x12 square (option b)
49
95
58
86
55
92
60
88
51
93
54
89
72
74
63
83
66
77
61
81
70
76
67
80
97
47
106
38
103
44
108
40
99
45
102
41
36
110
27
119
30
113
25
117
34
112
31
116
37
107
46
98
43
104
48
100
39
105
42
101
144
2
135
11
138
5
133
9
142
4
139
8
85
59
94
50
91
56
96
52
87
57
90
53
84
62
75
71
78
65
73
69
82
64
79
68
13
131
22
122
19
128
24
124
15
129
18
125
120
26
111
35
114
29
109
33
118
28
115
32
121
23
130
14
127
20
132
16
123
21
126
17
12
134
3
143
6
137
1
141
10
136
7
140



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Perfect magic squares|Contact / guestbook|3x3 magic square|3x3 magic square, explanation|Sudoku method (1)|Sudoku method (2)|Sudoku method (3)|Pan magic 4x4 square|Pan magic 4x4 square, explanation|Transformation method|Pan magic 5x5 square|Pan magic 5x5 square, explanation|6x6 magic square|Most perfect magic squares, explanation|Khajuraho method|Khajuraho method, explanation|Basic pattern method (1)|Basic pattern method (2)|Basic pattern method (3)|Analysis Franklin panm. 8x8|Basic key method (1)|Basic key method (2)|pan magic 9x9 square|Pan magic 15x15 square|The perfect magic square|Ultra pan magic 25x25 square|Pan magic 27x27 square|Pan magic 35x35 square|Bordered squares|Inlaid square|Each magic sum|Water retention challenge|Most magic 4x4x4 cube|Perfect magic 8x8x8 cube|Favorite Links