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The 3x3 magic square is square, because it has as many rows (from left to right = horizontal) as columns (from top to bottom
= vertical).
The 3x3 magic square consists of 3 rows which multiplied by 3 columns is 9 cells.
The 3x3 magic square must contain 9 different digits. A pure magic 3x3 square contains the digits 1, 2, 3, 4, 5, 6, 7, 8 and 9.
The magic square is magic, because the sum of the digits of each row, each column and both diagonals always give the same
result. The sum can be calculated as follows, the (odd) size of the square multiplied by the middle digit: 3 x 5 = 15.
What is the secret behind the 3x3 magic square?
The secret behind the 3x3 magic square is easy to explane. If you must take 3 (different) digits out of the digits 1 up to 9,
which total each time to 15, than there are the following possibilities:
1+5+9
1+6+8
2+4+9
2+5+8
2+6+7
3+4+8
3+5+7
4+5+6.
There are 8 possibilities.
The minimum features of the 3x3 square are 3 row features plus 3 column features plus 2 diagonal features total to 8 features.
Because there are 8 possibilities and 8 features, there is only one solution of the 3x3 magic square.
If we count the appearance of the 1, 2, 3, 4, 5, 6, 7, 8 and 9 in the 8 possibilities, than we get the following result:
1 = 2x
2 = 3x
3 = 2x
4 = 3x
5 = 4x
6 = 3x
7 = 2x
8 = 3x
9 = 2x
The middle cell takes part of the middle row, the middle column and both diagonals, that is 4 features. That is why you must
always put the 5 in the middle cell. The corners take part of one row, one column and one diagonal, that is 3 features. That
is why you must put the 2, 4, 6 and 8 (= even digits) always in the corners. Fill the digits 1, 3, 7 en 9 in the empty cells (in
the middle of the sides). Because you put the 5 in the middle, the sum of the other two cells of a diagonal must be (15 - 5 = )
10. To get the total of 10 with the even digits in the corners there are only two possibilities: 2+8 or 4+6. That is why you must
put 2 and 8 or 4 and 6 in the same diagonal.
Like I have already told, there is only one solution of the 3x3 magic square, that is excluding rotation and/or mirrorring (see
explanation on page ‘panmagic 4x4). Including rotation and/or mirroring there are (1 x 8 = ) 8 solutions of the 3x3 square
How to produce a 3x3 magic square?
A ‘trick’ to produce the 3x3 square is the diagonal method of (the Dutch) professor van der Blij:
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